How do you solve #-11k ^ { 2} - k = 7#?

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Answer 1 · 2017-09-09T11:00:56

Solution: #k ~~ -0.045 + 0.796 i , k ~~ -0.045 - 0.796 i #

# -11k^2 -k =7 or 11k^2 +k +7 =0# Comparing with standard

quadratic equation # ax^2+bx+c=0# we get here

#a=11, b=1 ,c=7 #, Discriminant # D= b^2-4ac = 1-4*11*7#

or #D=1-308=-307 # . If #D# is positive, we get two real

solutions, if #D=0# we get just one solution, and if it is negative

we get complex solutions.

# k= (-b+- sqrtD)/(2a)= (-1 +- sqrt (-307))/22 # or

#k= (-1 +- sqrt (307)i)/22 or k = -1/22+- sqrt (307)/22i# or

#k ~~ -0.045 + 0.796 i , k ~~ -0.045 - 0.796 i (3dp)# [Ans]