How do you solve #12- 2a = 10#?

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Answer 1 · 2017-06-27T19:12:41

See a solution process below:

First, subtract #color(red)(12)# from each side of the equation to isolate the #a# term while keeping the equation balanced:

#-color(red)(12) + 12 - 2a = -color(red)(12) + 10#

#0 - 2a = -2#

#-2a = -2#

Now, divide each side of the equation by #color(red)(-2)# to solve for #a# while keeping the equation balanced:

#(color(red)(cancel(color(black)(-2)))a)/cancel(color(red)(-2)) = 1#

#a = 1#