How do you solve #12> 4- \frac { 6y } { 7}#?

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Answer 1 · 2018-06-28T10:13:19

#y > -28/3#

As explained below:

#12>4-(6y)/7#

Subtract #4# both sides:

#12-4>(4-4)-(6y)/7#

#12-4>cancel(4-4)-(6y)/7#

#8 > -(6y)/7#

Multiply by #7# both sides:

#8 xx 7 > -(6y)/7 xx 7#

#56 > -(6y)/cancel7 xx cancel7#

#56> -6y#

When diving or multiplying by negative number, the inequality sign changes to opposite sign: #># changes to #<#

so now e get:

#56/-6< y#

#-28/3 < y#