First, subtract #color(red)(12)# from each side of the equation to isolate the #x# term while keeping the equation balanced:
#-color(red)(12) + 12 + 4/5x = -color(red)(12) - 16#
#0 + 4/5x = -28#
#4/5x = -28#
Now, multiply each side of the equation by #color(red)(5)/color(blue)(4)# to solve for #x# while keeping the equation balanced:
#color(red)(5)/color(blue)(4) xx 4/5x = color(red)(5)/color(blue)(4) xx -28#
#cancel(color(red)(5))/cancel(color(blue)(4)) xx color(blue)(cancel(color(black)(4)))/color(red)(cancel(color(black)(5)))x = color(red)(5)/color(blue)(4) xx (4 xx -7)#
#x = color(red)(5)/cancel(color(blue)(4)) xx (color(blue)(cancel(color(black)(4))) xx -7)#
#x = -35#