Question

How do you solve `12( g + 3) - 3g = 117`?

Answer 1

`g=9`

Explanation:

`12(g+3)-3g=117`

`12*g+12*3-3g=117`

9g+36=117#

`9g=117-36`

`cancel(9)g=cancel(81)`

`g=9`