How do you solve #12( x - 1) + 6x - 4> 2x#?

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Answer 1 · 2016-12-03T11:32:35

#x > 1#

Step 1) Expand the terms in parenthesis:

#12x - 12 + 6x - 4 > 2x#

Step 2) Next combine like terms on each side of the inequality:

#12x + 6x - 12 - 4 > 2x#

#18x - 16 > 2x#

Step 3) Isolate the #x# terms on one side of the inequality while keeping the inequality balanced:

#18x - 16 + 16 - 2x > 2x + 16 - 2x#

#16x - 0 > 0 + 16#

#16x > 16#

Step 4) Solve for #x# while keeping the inequality balanced:

#(16x)/16 > 16/16#

#1x > 1#

#x > 1#