How do you solve $12(x+3) - 3x = 117$ ?

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Answer 1 · 2016-05-12T21:08:35

Multiply out the brackets and collect like terms,
Then get all the x terms on one side and all the number terms on the other side. $x = 9$

$12(x + 3) - 3x = 117$

$12x + 36 color(red)(-36) - 3x = 117 color(red)(-36)$

$9x = 117 - 36 rArr 9x = 81$

$x = 9$

Answer 2 · 2016-05-12T21:09:45

$*x = 9*$

To solve this equation for the $x$ variable we begin by using the distributive property to eliminate the parenthesis

$12(x+3) -3x = 117$

$12x + 36 -3x = 117$

Next we combine like terms

$12x - 3x = 9x$

$9x + 36 = 117$

isolate the term with $x$ by subtracting $36$ from both sides

$9x cancel(+36) cancel(-36) = 117 -36$

$9x =81$

divide by $9$ on both sides to isolate the $x$

$(cancel9x)/cancel9= 81/9$

$*x = 9*$

How do you solve 12(x+3) - 3x = 11712(x+3) - 3x = 117?