How do you solve $12 x + 16 \leq 10 x$ $12x + 16 <= 10x$ ?

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Answer 1 · 2016-01-22T11:41:06

$12 x + 16 \leq 10 x$ $12x + 16 <= 10x$

$12 x - 10 x \leq - 16$ $12x - 10x <= -16$

$2 x \leq - 16$ $2x <= -16$

$x \leq - \frac{16}{2}$ $x <= -16/2$

$x \leq - 8$ $x <= -8$

So, $x$ $x$ is less than or equal to -8.

How do you solve 12x + 16 <= 10x12x+16≤10x12x + 16 <= 10x?