How do you solve 12x + 6\geq 9x + 1212x+69x+12?

1 Answer
Jan 16, 2018

See a solution process below:

Explanation:

First, subtract color(red)(6)6 and color(blue)(9x)9x from each side of the inequality to isolate the xx term while keeping the inequality balanced:

12x - color(blue)(9x) + 6 - color(red)(6) >= 9x - color(blue)(9x) + 12 - color(red)(6)12x9x+669x9x+126

(12 - color(blue)(9))x + 0 >= 0 + 6(129)x+00+6

3x >= 63x6

Now, divide each side of the inequality by color(red)(3)3 to solve for xx while keeping the inequality balanced:

(3x)/color(red)(3) >= 6/color(red)(3)3x363

(color(red)(cancel(color(black)(3)))x)/cancel(color(red)(3)) >= 2

x >= 2