How do you solve #13< 2x - 1< 17#?

1 Answer
EZ as pi
Oct 9, 2016

#7 < x < 9#

Explanation:

Solve this as two separate inequalities first, and then combine them at the end.

#13< 2x - 1< 17# can be split into:

#color(red)(13< 2x - 1)" and "color(blue)(2x -1< 17)#

#color(red)(13+1< 2x)" and "color(blue)(2x< 17+1)#

#color(red)(14< 2x)" and "color(blue)(2x< 18)#

#color(red)(7< x)" and "color(blue)(x< 9)" "larr# the x is the same

#color(white)(xxxxx)7 < x < 9#

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