How do you solve #-13<=3+8p<=11#?

1 Answer
Jim G.
Apr 15, 2018

#-2 <= p<= 1#

Explanation:

#"isolate 8p in the centre interval"#

#"subtract 3 from each of the 3 intervals"#

#-13color(red)(-3)<=cancel(3)cancel(color(red)(-3))+8p <=11color(red)(-3)#

#rArr-16 <= 8p <= 8#

#"divide each interval by 8"#

#rArr-2 <= p <=1#

#p in[-2,1]larrcolor(blue)"in interval notation"#

Related questions
Impact of this question
908 views around the world
You can reuse this answer
Creative Commons License