How do you solve #13\leq 1+ 2b#?

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Answer 1 · 2017-12-18T13:31:23

See a solution process below:

First, subtract #color(red)(1)# from each side of the inequality to isolate the #b# term while keeping the inequality balanced:

#13 - color(red)(1) <= 1 - color(red)(1) + 2b#

#12 <= 0 + 2b#

#12 <= 2b#

Now divide each side of the inequality by #color(red)(2)# to solve for #b# while keeping the inequality balanced:

#12/color(red)(2) <= (2b)/color(red)(2)#

#6 <= (color(red)(cancel(color(black)(2)))b)/cancel(color(red)(2))#

#6 <= b#

We can reverse or "flip" the entire inequality to state the solution in terms of #b#:

#b >= 6#