How do you solve $14+ 12s < 2$ ?

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Answer 1 · 2017-03-23T12:51:23

See the entire solution process below:

First, subtract $color(red)(14)$ from each side of the inequality to isolate the $s$ term while keeping the inequality balanced:

$-color(red)(14) + 14 + 12s < -color(red)(14) + 2$

$0 + 12s < -12$

$12s < -12$

Now, divide each side of the inequality by $color(red)(12)$ to solve for $s$ while keeping the inequality balanced:

$(12s)/color(red)(12) < -12/color(red)(12)$

$(color(red)(cancel(color(black)(12)))s)/cancel(color(red)(12)) < -1$

$s < -1$

How do you solve 14+ 12s < 214+ 12s < 2?