How do you solve #14+ 12s < 2#?

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Answer 1 · 2017-03-23T12:51:23

See the entire solution process below:

First, subtract #color(red)(14)# from each side of the inequality to isolate the #s# term while keeping the inequality balanced:

#-color(red)(14) + 14 + 12s < -color(red)(14) + 2#

#0 + 12s < -12#

#12s < -12#

Now, divide each side of the inequality by #color(red)(12)# to solve for #s# while keeping the inequality balanced:

#(12s)/color(red)(12) < -12/color(red)(12)#

#(color(red)(cancel(color(black)(12)))s)/cancel(color(red)(12)) < -1#

#s < -1#