Question

How do you solve `-14 + 3( x + 10) = 7( 2x + 4) + x`?

Answer 1

`x = -1`

Explanation:

Step 1. Remove the braces.

`- 14 + 3x + 30 = 14 x + 28 + x`

`-14 + 30 - 28 = 14 + x - 3x`

`12 x = -12`

`x = -1`

Answer 2

`x= -1`

Explanation:

`-14 + 3( x + 10) = 7( 2x + 4) + x`

Open brackets using distributive property:

`-14 + 3x + 30 = 14x + 28 + x`

Take the terms with variable `x` on left hand side and other terms on right hand side:

`3x- 14x-x = 28 +14- 30` =

`=> -12x=12`

`=> x= 12/-12`

`=>x= -1`

Answer 3

`x=-1`

Explanation:

`"distributing brackets on both sides of the equation"`

`-14+3x+30=14x+28+x`

`rArr3x+16=15x+28larrcolor(blue)"simplify both sides"`

`"subtract 15x from both sides"`

`3x-15x+16=cancel(15x)cancel(-15x)+28`

`rArr-12x+16=28`

`"subtract 16 from both sides"`

`-12xcancel(+16)cancel(-16)=28-16`

`rArr-12x=12`

`"divide both sides by "-12`

`(cancel(-12) x)/cancel(-12)=12/(-12)`

`rArrx=-1`

`color(blue)"As a check"`

`"substitute this value into the equation and if "`
`"both sides are equal then it is the solution"`

`"left "=-14+3(-1+10)=-14+27=13`

`"right "=7(-2+4)+(-1)=14-1=13`

`rArrx=-1" is the solution"`