Question

How do you solve `14v + 5( 4- 2v ) = 20`?

Answer 1

See a solution process below:

Explanation:

First, expand the terms in parenthesis on the left side of the equation by multiplying each term within the parenthesis by the term outside the parenthesis:

`14v + color(red)(5)(4 - 2v) = 20`

`14v + (color(red)(5) xx 4) - (color(red)(5) xx 2v) = 20`

`14v + 20 - 10v = 20`

`14v - 10v + 20 = 20`

`(14 - 10)v + 20 = 20`

`4v + 20 = 20`

Next, subtract `color(red)(20)` from each side of the equation to isolate the `v` term while keeping the equation balanced:

`4v + 20 - color(red)(20) = 20 - color(red)(20)`

`4v + 0 = 0`

`4v = 0`

Now, divide each side of the equation by `color(red)(4)` to solve for `v` while keeping the equation balanced:

`(4v)/color(red)(4) = 0/color(red)(4)`

`(color(red)(cancel(color(black)(4)))v)/cancel(color(red)(4)) = 0`

`v = 0`