Question

How do you solve `14x^2 + 28x = 9`?

Answer 1

`-1 +- sqrt(23/14)`

Explanation:

Divide both sides by 14 -->
`x^2 + 2x = 9/14`
`(x^2 + 2x + 1) = 9/14 + 1 = 23/14`
`(x + 1)^2 = 23/14`
`x + 1 = +- sqrt(23/14)`
`x = - 1 +- sqrt(23/14)`