How do you solve #15= 2x + 5x + 1#?

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Answer 1 · 2018-06-23T06:41:06

#x=2#

Add the like variables as shown below:

#15 = 2x + 5x +1#

#15 = 7x +1#

Subtract #1# both sides:

#15 - 1 = 7x + 1 -1#

#15 - 1 = 7x + cancel(1 -1)#

#14 = 7x#

Divide by #7# both sides:

#14/7 = (7x)/7#

#14/7 = (cancel7x)/cancel7#

#2=x#

Therefore, #x=2#

Check the answer:

#2(2) + 5(2) +1 = 4 + 10 +1 = 15# ----> Correct!