Question

How do you solve `15= 3\cdot 4^ { 6t }`?

Answer 1

Solution: `t ~~ 0.1935`

Explanation:

`15= 3*4^(6t) or 4^(6t)= 15/3 or 4^(6t)= 5`

Taking log on both sides we get

`6t*log 4 = log 5 or 6t = log 5/log 4 ~~ 1.160964` or

`t ~~ 1.160964/6 ~~0.1935 (4dp)`

Solution: `t ~~ 0.1935 (4dp)` [Ans]