How do you solve #15 - 4x + 5= 32#?

1 Answer
Jun 17, 2017

See a solution process below:

Explanation:

First, group and combine like terms on the left side of the equation. For this problem this will be the constants:

#15 - 4x + 5 = 32#

#-4x+ 15 + 5 = 32#

#-4x+ (15 + 5) = 32#

#-4x+ 20 = 32#

Next, subtract #color(red)(20)# from each side of the equation to isolate the #x# term while keeping the equation balanced:

#-4x+ 20 - color(red)(20) = 32 - color(red)(20)#

#-4x+ 0 = 12#

#-4x = 12#

Now, divide each side of the equation by #color(red)(-4)# to solve for #x# while keeping the equation balanced:

#(-4x)/color(red)(-4) = 12/color(red)(-4)#

#(color(red)(cancel(color(black)(-4)))x)/cancel(color(red)(-4)) = -3#

#x = -3#