How do you solve #15- 6x = - 3x + 6#?

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Answer 1 · 2017-06-23T10:02:14

See a solution process below:

First, add #color(red)(6x)# and subtract #color(blue)(6)# from each side of the equation to isolate the #x# term while keeping the equation balanced:

#15 - 6x + color(red)(6x) - color(blue)(6) = -3x + 6 + color(red)(6x) - color(blue)(6)#

#15 - color(blue)(6) - 6x + color(red)(6x) = -3x + color(red)(6x) + 6 - color(blue)(6)#

#9 - 0 = (-3 + color(red)(6))x + 0#

#9 = 3x#

Now, divide each side of the equation by #color(red)(3)# to solve for #x# while keeping the equation balanced:

#9/color(red)(3) = (3x)/color(red)(3)#

#3 = (color(red)(cancel(color(black)(3)))x)/cancel(color(red)(3))#

#3 = x#

#x = 3#