How do you solve #-15t + 15= - 3( 5t - 5)#?

2 Answers
Tony B
Sep 21, 2016

#color(red)("Is the question correct?")#

Explanation:

Multiply out the bracket givimg:

#-15t+15 = -15t+15# ???????

This is a bit like saying a cat is a cat!

EZ as pi
Sep 21, 2016

#x# has any value. #x in RR#

Explanation:

#-15t +15 = -3(5t-5)" "larr# remove brackets

#-15t +15 = -15t +15" "larr# looks a bit strange? Carry on..

#-15t +15t = 15-15#

#0=0" "larr# but there is no #x#?

We have ended up with a TRUE statement, but there is no #X# left to solve for?

This is a special kind of equation called an identity, which is true for any value of x.
The clue is if you end up with #x=x, " "8 = 8, " "0=0" " #etc

#x# has any value. #x in RR#

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