How do you solve #15w = 6w + 81#?

Question

640 views around the world

You can reuse this answer
Creative Commons License

Answer 1 · 2017-09-15T20:54:57

See a solution process below:

First, subtract #color(red)(6w)# from each side of the equation to isolate the #w# term while keeping the equation balanced:

#-color(red)(6w) + 15w = -color(red)(6w) + 6w + 81#

#(-color(red)(6) + 15)w = 0 + 81#

#9w = 81#

Now, divide each side of the equation by #color(red)(9)# to solve for #w# while keeping the equation balanced:

#(9w)/color(red)(9) = 81/color(red)(9)#

#(color(red)(cancel(color(black)(9)))w)/cancel(color(red)(9)) = 9#

#w = 9#