# How do you solve -16+0.2(10^x)=35?

$x = \log 255 \approx 2.407$

#### Explanation:

$- 16 + 0.2 \left({10}^{x}\right) = 35$

Let's move all the non-x terms to the right side:

$0.2 \left({10}^{x}\right) = 51$

${10}^{x} = \frac{51}{0.2} = 255$

Now we can take the log of both sides:

$\log {10}^{x} = \log 255$

$x \log 10 = \log 255$

Remember that $L o {g}_{10} 10 = 1$, so:

$x = \log 255 \approx 2.407$