# How do you solve #16^ { - 2v } = 64^ { 2v }#?

##### 2 Answers

Jul 28, 2018

#### Explanation:

Jul 28, 2018

#### Explanation:

#"express 16 and 64 in base 4"#

#(4^2)^(-2v)=(4^3)^(2v)#

#4^(-4v)=4^(6v)#

#"equating the exponents gives"#

#-4v=6vrArr2v=0rArrv=0#