How do you solve #16>=4(z-7)#?

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Answer 1 · 2016-11-19T22:46:37

#z <= 11#

Perform the necessary mathematics to isolate and solve for #z# while keeping the inequality balanced:

First, expand the terms within parentheis:

#16 >= (4*z) - (4*7)#

#16 >= 4z - 28#

Next, add 28 to both sides of the inequality:

#16 + 28 >= 4z - 28 + 28#

#44 >= 4z - 0#

#44 >= 4z#

Then, divide each side of the inequality by 4:

#44/4 >= (4z)/4#

#11 >= (4/4)z#

#11 >= 1z#

#11 >= z#

Finally, "flip" the inequality to put the answer in terms of #z#

#z <= 11#