How do you solve #16^(n-7)+5=24#?

1 Answer
Sep 4, 2016

#n = 8.06198#

Explanation:

Isolate the term with the variable.

#16^(n-7) = 19#

19 is clearly not an exact power of 16.
The variable is in the index, so use logs.

#log16^(n-7) = log19#

#(n-7)log16 = log19#

#(n-7) = log19/log16#

#n-7 = 1.06198#

#n = 8.06198#