How do you solve #17= 3( r - 5) + 8#?

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Answer 1 · 2017-09-14T10:18:51

See a solution process below:

First, subtract #color(red)(8)# from each side of the equation to isolate the term with the parenthesis while keeping the equation balanced:

#17 - color(red)(8) = 3(r - 5) + 8 - color(red)(8)#

#9 = 3(r - 5) + 0#

#9 = 3(r - 5)#

Next, divide each side of the equation by #color(red)(3)# to eliminate the need for parenthesis while keeping the equation balanced:

#9/color(red)(3) = (3(r - 5))/color(red)(3)#

#3 = (color(red)(cancel(color(black)(3)))(r - 5))/cancel(color(red)(3))#

#3 = r - 5#

Now, add #color(red)(5)# to each side of the equation to solve for #r# while keeping the equation balanced:

#3 + color(red)(5) = r - 5 + color(red)(5)#

#8 = r - 0#

#8 = r#

#r = 8#