How do you solve #17- x = 1+ 3x#?

1 Answer
Dec 5, 2016

#x = 4#

Explanation:

First, isolate the variables or #x# terms on one side of the equation and the constants on the other side of the equation while keeping the equation balanced:

17 - x + x - 1 = 1 + 3x + x - 1#

#17 - 0 - 1 = 1 - 1 + 3x + x#

#17 - 1 = 0 + 3x + x#

#17 - 1 = 3x + x#

Next we can consolidate like terms:

#16 = (3 + 1)x#

#16 = 4x#

Finally, we can solve for #x# while keeping the equation balanced:

#16/4 = (4x)/4#

#4 = (cancel(4)x)/cancel(4)#

#4 = x# or #x = 4#