How do you solve #(18) ^ { - 3} ( 18) ^ { n } = 18^ { - 11}#?

2 Answers
Jan 16, 2018

#n=-8#

Explanation:

First, remember that: #a^b*a^c=a^(b+c)#

Therefore, #18^-3*18^n=18^(-3+n)#

Now, since both #18^(-3+n)# and #18^-11# have the base of 18, we can say that #-3+n=-11#.

Therefore,
#n=-8#

Aug 6, 2018

#n=-8#

Explanation:

Recall the exponent property

#x^ax^b=x^(a+b)#

When we multiply exponents, we add the powers. To find #n#, we can essentially setup the equation

#-3+n=-11#

Adding #3# to both sides, we get

#n=-8#

Hope this helps!