Question

How do you solve `2.0x - 4.8+ 0.5x = 15.2`?

Answer 1

`2x-48/10+5/10x=152/10`
Add `48/10` to both sides
`2xcancel(-48/10)cancel(+48/10)+5/10x=152/10+48/10`
Gives
`2x+5/10x=20`
Note that `2=2/1,4/2.......20/10`
By that
`(20x+5x)/10=20`
Solve
`(25x)/10=20`
Multiply both sides by 10
`(25x)/cancel10 xx cancel10 = 20 xx 10`
`25x=200`
Divide both sides by 25
`(cancel25 x)/(cancel25)=(cancel200^8)/(cancel25^1)`
`x=8`

Answer 2

See a solution process below:

Explanation:

First, group and combine like terms on the left side of the equation:

`2.0x + 0.5x - 4.8 = 15.2`

`(2.0 + 0.5)x - 4.8 = 15.2`

`2.5x - 4.8 = 15.2`

Next, add `color(red)(4.8)` to each side of the equation to isolate the `x` term while keeping the equation balanced:

`2.5x - 4.8 + color(red)(4.8) = 15.2 + color(red)(4.8)`

`2.5x - 0 = 20`

`2.5x = 20`

Now, divide each side of the equation by `color(red)(2.5)` to solve for `x` while keeping the equation balanced:

`(2.5x)/color(red)(2.5) = 20/color(red)(2.5)`

`(color(red)(cancel(color(black)(2.5)))x)/cancel(color(red)(2.5)) = 8`

`x = 8`