How do you solve #-2( 1+ 2x ) = - 10- 8x#?

1 Answer
Jim G.
Sep 1, 2017

#x=-2#

Explanation:

#"distribute bracket on left side of equation"#

#-2-4x=-10-8x#

#"collect terms in x on the left side and numeric values on"#
#"the right side"#

#"add 8x to both sides"#

#-2-4x+8x=-10cancel(-8x)cancel(+8x)#

#rArr-2+4x=-10#

#"add 2 to both sides"#

#cancel(-2)cancel(+2)+4x=-10+2#

#rArr4x=-8#

#"divide both sides by 4"#

#(cancel(4) x)/cancel(4)=(-8)/4#

#rArrx=-2#

#color(blue)"As a check"#

Substitute this value into the equation and if both sides are equal then it is the solution.

#"left "=-2(1-4)=-2xx-3=6#

#"right "=-10-(-16)=-10+16=6#

#rArrx=-2" is the solution"#

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