#2(2 - 2x) = 4 - 8(1 - x)#
We can expand the brackets.
#4 - 4x = 4 - 8(1 - x)#
#4 - 4x = 4 - 8 - - 8x#
#4 - 4x = 4 - 8 + 8x#
#4 - 4x = -4 + 8x#
We can Move the #4# over to the right side.
# - 4x = -4 + 8x - 4#
We can Move the #-8x# over to the left side.
# - 4x - 8x = -4 - 4#
#we can solve these equations.
# -12x = -4 - 4#
# -12x = -8#
We can isolate #x# by moving #-12# to the other side of the equation.
#x = -8 ÷ -12#
#color(blue)(x = 2/3 or 0.66dot6#
We can prove our answer by substituting #2/3# for #x# in the equation and see if we are correct.
#2(2 - 2x) = 4 - 8(1 - x)#
#2(2 - 2 xx 2/3) = 4 - 8(1 - 2/3)#
Now we can use #"BODMAS"# or #"PEMDAS"# to solve the equation.
#"BOMDAS"# = Brackets, Order (Power), Multiplication, Division, Addition and Subtraction
#"PEMDAS"# = Power, Exponents, Multiplication, Division, Addition and Subtraction
#2(2 - 2 xx 2/3) = 4 - 8(1 - 2/3)#
#2(2 - 1 1/3) = 4 - 8(1 - 2/3)#
#2(2 - 1 1/3) = 4 - 8(1/3)#
#2 xx 2/3 = 4 - 8(1/3)#
#2 xx 2/3 = 4 - 2 2/3#
#2 xx 2/3 = 1 1/3#
#1 1/3 = 1 1/3#
