How do you solve #2. 22- 3x = 7#?

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Answer 1 · 2018-01-30T18:37:03

See a solution process below:

First, subtract #color(red)(2.22)# from each side of the equation to isolate the #x# term while keeping the equation balanced:

#2.22 - color(red)(2.22) - 3x = 7 - color(red)(2.22)#

#0 - 3x = 4.78#

#-3x = 4.78#

Now, divide each side of the equation by #color(red)(-3)# to solve for #x# while keeping the equation balanced:

#(-3x)/color(red)(-3) = 4.78/color(red)(-3)#

#(color(red)(cancel(color(black)(-3)))x)/cancel(color(red)(-3)) = -1.59bar3#

#x = -1.59bar3#

#x = -1.59# rounded to the nearest hundredth.