How do you solve #2( 3+ x ) \geq 15- 5x#?

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Answer 1 · 2018-04-10T02:22:57

#x≥9/7#

#2(3+x)≥15-5x# (Distribute #2# to the numbers in braces)

#6+2x≥15-5x# (Subtract #6# from both sides)

#2x≥9-5x# (Add #5x# to both sides)

#7x≥9# (Divide both sides by #7#)

#x≥9/7#

Answer 2 · 2018-04-10T02:26:35

#x>=9/7#

Solve:

#2(3+x)>= 15-5x#

Expand the left-hand side.

#6 +2x>=15-5x#

Add #5x# to both sides.

#6+2x+5x>=15#

Subtract #6# from both sides.

#2x+5x>15-6#

Simplify.

#7x>=9#

Divide both sides by #7#.

#x>=9/7#