How do you solve #2= 3x + 3( 2x - 6)#?

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Answer 1 · 2018-03-25T20:38:03

#x=20/9#

First expand the parentheses:

#2=3x+3(2x-6)#

#2=3x+(3*2x)+(3*-6)#

#2=3x+6x-18#

Now combine similar terms:

#2=(3+6)x-18#
#2=9x-18#

Add 18 to both sides of the equation:

#18+2=9xcancel(-18)+cancel(18)#

#20=9x#

Now divide each side by 9:

#20/9=(cancel(9)x)/cancel(9)#

#x=20/9#