How do you solve #2/(3x) + 5 = 4/x#?

1 Answer
Mar 22, 2018

#x=2/3#

Explanation:

Solve:

#2/(3x)+5=4/x#

Multiply both sides by #3x#.

#3x(2/(3x)+5)=(4xx3x)/x#

Cancel.

#color(red)cancel(color(black)(3x))(2/(color(red)cancel(color(black)(3x))))+5xx3x=(4/color(red)cancel(color(black)(x)))3color(red)cancel(color(black)(x))#

Simplify.

#2+5xx3x=4xx3#

#2+15x=12#

Subtract #2# from both sides.

#2-2+15x=12-2#

Simplify.

#0+15x=10#

#15x=10#

Divide both sides by #15#.

#(color(red)cancel(color(black)(15))^1x)/color(red)cancel(color(black)(15))^1=10/15#

#x=10/15#

Reduce by dividing the numerator and denominator by #5#.

#x=(10-:5)/(15-:5)#

#x=2/3#