How do you solve $-2( 3x + 5) = 8$ ?

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Answer 1 · 2017-03-29T22:16:19

$x=-3$

Divide $-2$ on both sides:

$3x+5=8/-2 = -4$

Subtract 5 on both sides:

$3x=-4-5 = -9$

Divide both sides by 3:

$x=-9/3=-3$

How do you solve -2( 3x + 5) = 8-2( 3x + 5) = 8?