Question

How do you solve `2( 4a + 1) = 4( 2a - 1) + 6`?

Answer 1

The given equation is true for any value `a in RR` (or `in CC`, for that matter).

Explanation:

Both `2(4a+1)` and `4(2a-1)+6`
are `=8a+2`

and `8a+2=8a+2` for any value of `a`