How do you solve #-2( 4p + 6) \geq 5p + 40#?

1 Answer
May 2, 2017

See the entire solution process below:

Explanation:

First, expand the term in parenthesis on the left side of the inequality by multiplying each term within the parenthesis by the term outside the parenthesis:

#color(red)(-2)(4p + 6) >= 5p + 40#

#(color(red)(-2) * 4p) + (color(red)(-2) * 6) >= 5p + 40#

#-8p + (-12) >= 5p + 40#

#-8p - 12 >= 5p + 40#

Next, add #color(red)(8p)# and subtract #color(blue)(40)# from each side of the inequality to isolate the #p# term while keeping the inequality balanced:

#color(red)(8p) - 8p - 12 - color(blue)(40) >= color(red)(8p) + 5p + 40 - color(blue)(40)#

#0 - 52 >= (color(red)(8) + 5)p + 0#

#-52 >= 13p#

Now, divide each side of the inequality by #color(red)(13)# to solve for #p# while keeping the inequality balanced:

#-52/color(red)(13) >= (13p)/color(red)(13)#

#-4 >= (color(red)(cancel(color(black)(13)))p)/cancel(color(red)(13))#

#-4 >= p#

We can state the solution in terms of #p# by reversing or "flipping" the entire inequality:

#p <= -4#