Question

How do you solve `-2( 6+ s ) \geq - 15- 23`?

Answer 1

`s <= 13`

Explanation:

First, combine like terms and expand the term in parenthesis:

`-2*6 + -2s >= -38`

`-12 - 2s >= -38`

Next, isolate the `s` term:

`-12 + 12 - 2s >= -38 + 12`

`0 - 2s >= -26`

`-2s >= -26`

`Now we can solve for`s#. However, we must remember, when dealing with inequalities if you multiply or divide by a negative number it reverses the inequality:

`(-2s)/-2 <= (-26)/(-2)`

`(cancel(-2)s)/cancel(-2) <= 13`

`s <= 13`