How do you solve #2( - 6x - 1) = 8x - 6#?

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Answer 1 · 2016-12-04T21:57:18

#x = 1/5#

First, expand the term within parenthesis:

#-12x - 2 = 8x - 6#

#next, isolate the #x# terms on one side of the equation and the constants on the other side of the equation while keeping the equation balanced:

#-12x + 12x - 2 + 6 = 8x + 12x - 6 + 6#

#0 - 2 + 6 = 20x - 0#

#4 = 20x#

Now. solve for #x# while keeping the equation balanced:

#(4)/20 = (20x)/20#

#(4/4)*((1)/5) = (cancel(20)x)/cancel(20)#

#x = 1/5