How do you solve $2( - 6x - 1) = 8x - 6$ ?

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Answer 1 · 2016-12-04T21:57:18

$x = 1/5$

First, expand the term within parenthesis:

$-12x - 2 = 8x - 6$

$next, isolate the$ x# terms on one side of the equation and the constants on the other side of the equation while keeping the equation balanced:

$-12x + 12x - 2 + 6 = 8x + 12x - 6 + 6$

$0 - 2 + 6 = 20x - 0$

$4 = 20x$

Now. solve for $x$ while keeping the equation balanced:

$(4)/20 = (20x)/20$

$(4/4)*((1)/5) = (cancel(20)x)/cancel(20)$

#x = 1/5

How do you solve 2( - 6x - 1) = 8x - 62( - 6x - 1) = 8x - 6?