How do you solve #2+ 6x = 2+ x#?

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Answer 1 · 2017-11-20T22:47:34

See a solution process below:

First, subtract #color(red)(2)# and #color(blue)(x)# from each side of the equation to isolate the #x# term while keeping the equation balanced:

#2 - color(red)(2) + 6x - color(blue)(x) = 2 - color(red)(2) + x - color(blue)(x)#

#0 + 6x - color(blue)(1x) = 0 + 0#

#(6 - color(blue)(1))x = 0#

#5x = 0#

Now, divide each side of the equation by #color(red)(5)# to solve for #x# while keeping the equation balanced:

#(5x)/color(red)(5) = 0/color(red)(5)#

#(color(red)(cancel(color(black)(5)))x)/cancel(color(red)(5)) = 0#

#x = 0#