How do you solve #2^(7x) = 2#?

1 Answer
Özgür Özer
Dec 10, 2015

#color(white)(xxx)x=1/7#

Explanation:

#color(white)(xxx)2^(7x)=2#

First method: Exponentiation
#color(white)(xxx)2^(7x)=2^1#
#=>(7x)/color(red)7=1/color(red)7#
#=>x=1/7#

Second method: Logarithm
#color(white)(xxx)7x=log_2 2#
#=>(7x)/color(red)7=1/color(red)7#
#=>x=1/7#

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