How do you solve #2= 8\cdot ( - 6) + b#?
1 Answer
Mar 4, 2017
Explanation:
#"Solving "2=(8xx-6)+b#
#rArr2=-48+b# Isolate b by adding 48 to each side of the equation.
#2+48=cancel(-48)cancel(+48)+b#
#rArr50=b" or "b=50#
