How do you solve $2( 9t - 1) + 3= 13$ ?

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Answer 1 · 2017-06-10T22:28:13

See a solution process below:

First, subtract $color(red)(3)$ from each side of the equation to isolate the term with parenthesis while keeping the equation balanced:

$2(9t - 1) + 3 - color(red)(3) = 13 - color(red)(3)$

$2(9t - 1) + 0 = 10$

$2(9t - 1) = 10$

Next, divide each side of the equation by $color(red)(2)$ to isolate the parenthesis while keeping the equation balanced:

$(2(9t - 1))/color(red)(2) = 10/color(red)(2)$

$(color(red)(cancel(color(black)(2)))(9t - 1))/cancel(color(red)(2)) = 5$

$9t - 1 = 5$

Then, add $color(red)(1)$ to each side of the equation to isolate the $t$ term while keeping the equation balanced:

$9t - 1 + color(red)(1) = 5 + color(red)(1)$

$9t - 0 = 6$

$9t = 6$

Now, divide each side of the equation by $color(red)(9)$ to solve for $t$ while keeping the equation balanced:

$(9t)/color(red)(9) = 6/color(red)(9)$

$(color(red)(cancel(color(black)(9)))t)/cancel(color(red)(9)) = (3 xx 2)/color(red)(3 xx 3)$

$t = (color(red)(cancel(color(black)(3))) xx 2)/color(red)(color(black)(cancel(color(red)(3))) xx 3)$

$t = 2/3$

How do you solve 2( 9t - 1) + 3= 132( 9t - 1) + 3= 13?