First, subtract #color(red)(3)# from each side of the equation to isolate the term with parenthesis while keeping the equation balanced:

#2(9t - 1) + 3 - color(red)(3) = 13 - color(red)(3)#

#2(9t - 1) + 0 = 10#

#2(9t - 1) = 10#

Next, divide each side of the equation by #color(red)(2)# to isolate the parenthesis while keeping the equation balanced:

#(2(9t - 1))/color(red)(2) = 10/color(red)(2)#

#(color(red)(cancel(color(black)(2)))(9t - 1))/cancel(color(red)(2)) = 5#

#9t - 1 = 5#

Then, add #color(red)(1)# to each side of the equation to isolate the #t# term while keeping the equation balanced:

#9t - 1 + color(red)(1) = 5 + color(red)(1)#

#9t - 0 = 6#

#9t = 6#

Now, divide each side of the equation by #color(red)(9)# to solve for #t# while keeping the equation balanced:

#(9t)/color(red)(9) = 6/color(red)(9)#

#(color(red)(cancel(color(black)(9)))t)/cancel(color(red)(9)) = (3 xx 2)/color(red)(3 xx 3)#

#t = (color(red)(cancel(color(black)(3))) xx 2)/color(red)(color(black)(cancel(color(red)(3))) xx 3)#

#t = 2/3#