How do you solve #-2\frac { 2} { 3} n + 21= - \frac { 1} { 3}#?

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Answer 1 · 2016-11-03T21:48:11

#n = 16#

First multiple each side of the equation by #3# to eliminate the fractions and then solve for #n# while keeping the equation balanced:

#3(-2(2/3)n + 21) = 3(-1/3)#

#-(3/3)2*2n + (3*21) = (3/3)*-1#

#-2*2n + 63 = -1#

#-4n + 63 = -1#

#-4n + 63 + 4n + 1 = -1 + 4n + 1#

#64 = 4n#

#64/4 = (4n)/4#

#16 = n#