Question

How do you solve `-2(n-2)=5n+3(n-2)`?

Answer 1

First get rid of the parentheses, then put all the `n`'s to one side and the numbers to the other:

Explanation:

`->-2*n-2*(-2)=5*n+3*n+3*(-2)`
`->-2n+4=5n+3n-6`

Add `2n` to both sides:
`->cancel(2n)-cancel(2n)+4=2n+5n+3n-6`

Now add `6` to both sides:
`->6+4=2n+5n+3n+cancel6-cancel6`
`->10=10n->n=1`