How do you solve #2=\sqrt{64-x^{2}}#?

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Answer 1 · 2018-01-27T04:30:30

#x=+-2sqrt(15)#

#2=sqrt(64-x^2)#

Square both sides to get

#4=64-x^2#

#:.x^2=60#

#x=+-sqrt(60)#

#x=+-sqrt(4*15)#

#x=+-2sqrt(15)#