How do you solve #[2\times (-3)^{2}-8]\div 2#?

1 Answer
Patrick H. · EZ as pi
Nov 13, 2016

Use the PEMDAS method.

Explanation:

PEMDAS stands for:

Parentheses
Exponents
Multiplication
Division
Addition
Subtraction

We must solve the equation in that order. We have a pair of parentheses, so let's solve that. We will solve the exponents, then we will multiply and subtract:

#-3^2=9#
#2*9-8#
#18-8=10#

We now have #10/2#, which gives us our answer of #5#.

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