How do you solve #2( v + 4) < 3( 1- v )#?
1 Answer
Nov 17, 2016
Explanation:
Distribute the brackets on both sides of the inequality.
#2v+8<3-3v# add 3v to both sides.
#2v+3v+8<3cancel(-3v)cancel(+3v)#
#rArr5v+8<3# subtract 8 from both sides.
#5vcancel(+8)cancel(-8) <3-8#
#rArr5v<-5# To solve for v, divide both sides by 5.
#(cancel(5) v)/cancel(5)<(-5)/5#
#rArrv<-1" is the solution"#
